Question

The lines `x+2y+3=0,x+2y-7=0,a n d2x-y-4=0` are the sides of a square. The equation of the remaining side of the square can be `2x-y+6=0` (b) `2x-y+8=0` `2x-y-10=0` (b) `2x-y-14=0`
A. 2x-y+6=0
B. 2x-y+8=0
C. 2x-y-10=0
D. 2x-y-14=0

Answer 1

Correct Answer - A::D
Distance between x+2y+3 = 0 and x+2y-7 = 0 si `10//sqrt(5)`. Let the remaining side parallel to 2x-y-4=0 be `2x-y+lambda = 0`. We have `(|lambda +4|)/(sqrt(5)) = (10)/(sqrt(5)) " or " lambda =6, -14`
Thus, the remaining side is 2x-y+6 = 0 2x-y-14=0.