Question

The block of mass `M` moving on the frictionless horizontal surface collides with the spring constant `k` and compresses it by length `L` . The maximum momention of the block after collision is

A. Zero
B. `(ML^(2))/(K)`
C. `Lsqrt(MK)`
D. `(KL^(2))/(2M)`

Answer 1

Correct Answer - C
`(1)/(2)MV^(2)=(KL)/(2)=(P^(2))/(2M)`
`P=Lsqrt(KM)`