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If the distances of one focus of hyperbola from its directrices are 5 and 3, then its eccentricity is
A. `sqrt2`
B. 2
C. 4
D. 8

1 Answer

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Best answer
Correct Answer - B
We have
`ae-(a)/(e)=3and ae+(a)/(e)=5`
`therefore" "ae=4and (1)/(e)=1`
`therefore" "a^(2)=4`
`therefore" "a=2`
`therefore" "e=2`

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