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Find the value of `tan^(-1) (-tan.(13pi)/(8)) + cot^(-1) (-cot((9pi)/(8)))`

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Find the value of `tan^(-1) (-tan.(13pi)/(8)) + cot^(-1) (-cot((9pi)/(8)))`
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Correct Answer - `pi`
`tan^(-1) (-tan.(13pi)/(8)) + cot^(-1) (-cot ((19pi)/(8)))`
`= - tan^(-1) (tan.(13pi)/(8)) + pi - cot^(-1) (cot ((19pi)/(8)))`
`= -((13pi)/(8) - 2pi) + pi - ((19 pi)/(8) - 2pi)`
`= (3pi)/(8) + (5pi)/(8) = pi`
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