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Point A and B are in the first quadrant,point O is the origin. If the slope of OA is 1,slope of OB is 7 and OA=OB,Then slope of AB is: a. -1/5 b. -1/4 c. -1/3 d. -1/2
A. `-1//5`
B. `-1//4`
C. `-1//3`
D. `-1//2`

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Correct Answer - D
`tantheta=7`
` OA=OB=r`
`sintheta=(7)/(5sqrt2)costheta=(1)/(5sqrt2)`
Now, `m_(AB)=1//2`.
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