Let there is x charge on left side of sheet and `Q-x` charge on right side of sheet.
since, point P lies inside the conductor, so `E_(P)=O`
or `x/(2Aepsi_(0))-(Q-x)/(2Aepsi_(0))=0" "implies" "(2x)/(2Aepsi_(0))=Q/(2Aepsi_(0))`
`implies x=Q/2` ^ `Q-x=Q/2`
So, charge is equally distributed on both sides.