A 60kg man is running on horizontal road with acceleration `2ms^(-1)` friction coefficient between foot of the man and the ground is `mu=0.4` then
A. Frictional force acting on the man is 120N
B. Frictional force acting on the man is 240N
C. Work done by friction on the man during his 2m displacement will be 240J
D. Direction of the frictional force acting on the man is opposite to his direction of motion.
