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Two elements A and B are such that Bond energy of A-A,B-B `&` A-B are respectively 81 Kcal/mol, 64 Kcal/mol and 88 Kcal/mol. If electronegativity of B is 3 then electronegativity of A may be
A. 1.9
B. 2.168
C. 3.832
D. 4.2

1 Answer

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`sqrt(E_(A-A)xxE_(B-B))=sqrt(81xx64)=72`
`Delta=E_(A-B)-sqrt(E_(A-A)xxE_(B-B))=90-72=18`
`|X_(A)-X_(B)|=0.208sqrt(A)=0.208sqrt(18)=0.88`
`X_(A)-30.88rArrX_(A)=3.88`
`3-X_(A)=0.88rArrX_(A)=2.12`

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