Question

A particle is projected at an angle of `45^(@)` with the horizontal with a speed u in a uniform gravitational field, as shown in the figure. The instaneous angular speed of the particle w.r.t. Point of projection at the moment if falls at the same horizontal level equals

A. `sqrt(2g)/(u)`
B. `(g)/(sqrt(2u)`
C. `(g)/(2sqrt(2)u)`
D. none of the above

Answer 1

`omega=((u)/sqrt(2))/((u^(2)sin90^(@))/(8))=(g)/sqrt(2u)`