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in Physics by (24.9k points)
Find centre of mass of given rod of linear mass density `lambda=(a+b(x/l)^2)` , x is distance from one of its end. Length of the rod is `l`.
A. `(3l)/4((3a+b)/(2a+b))`
B. `(3l)/4((2a+b)/(3a+b))`
C. `(l)/4((2a+b)/(3a+b))`
D. `l((2a+b)/(3a+b))`

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