Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
96 views
in Binomial Theorem by (91.2k points)
closed by
If `(1+x)^5=a_0+a_1x+a2x2+a_3x^3=a_4x^4+a_5x^5,` then the value of `(a_0-a_2+a_4)^2+(a_1-a_3+a_5)^2` is equal to `243` b. `32` c. `1` d. `2^(10)`
A. 243
B. 32
C. 1
D. `2^(10)`

1 Answer

0 votes
by (94.1k points)
selected by
 
Best answer
Correct Answer - B
Put `x = i`
`(1+i)^(5) = (a_(0) - a_(2) + a_(4)) + i(a_(1)-a_(3)+a_(5))`
`rArr |1+i|^(5) = |(a_(0) - a_(2) + a_(4)) + i(a_(1) - a_(3) + a_(5))|`
`rArr (a_(0)-a_(2)+a_(4))^(2)+(a_(1)-a_(3)+a_(5))^(2)=2^(5) = 32`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...