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If `x=m x+c` touches the parabola `y^2=4a(x+a),` then `c=a/m` (b) `c=a m+a/m` `c=a+a/m` (d) none of these
A. `c=(1)/(m)`
B. `c=am+(a)/(m)`
C. `c=a+(a)/(m)`
D. none of these

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Correct Answer - B
(2) The equation of tangent to the given parabola having slope m is
`y=m(x+a)+(a)/(m)`
`ory=mx+am+(a)/(m)`
Comparing (1) with y=mx+c, we have
`c=am+(a)/(m)`

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