Correct Answer - b
`vecr.veca= vecr.vecb= vecr.vecc=0 ` only if `veca,vecb and vecc` are coplanar, thus,
`[veca vecb vecc] =0`
Hence, statement 2 is true
Also `[veca -vecb vecb-vecc vecc-veca]=0 " even " if [veca vecb vecc] ne 0`
Hence, statement 2 is not the correct explanation for statement 1.