Question

Calculate the equilibrium constant for the reaction at 298 K
`Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s)`
Given` " " E_(Zn^(2+)//Zn)^(@)=-0.76 V` and `E_(Cu^(2+)//Cu)^(@)=+0.34 V`

Answer 1

`DeltaG^(@)=-"RT In Kc "=-2.303" RT log Kc"`
`therefore" "-212300=-2.303xx8.314xx298xxlog Kc`
`"or "log Kc =(212300)/(2.303xx8.314xx298)=37.2074`
`Kc" = Antilog "37.2074=1.6xx10^(37)`