Question

In the last question, the electric field in vertical direction is switched off and a field of same strength`(E_0)` is switched on in horizontal direction. Find the horizontal velocity of the ball during the `n^(th)` collision. Also calculate the time interval between `n^(th)` and `(n + 1)^(th)` collision

Answer 1

Correct Answer - `V_(xn)=(qE)/(m)sqrt((2h)/(g))[1+2e((1-e^(n-1))/(1-e))}` and `T=2e^(n)sqrt((2h)/(g))`