Question

Two identical vessels are connected by a tube with a valve letting the gas pass from one vessel into the other if the pressure difference Δp ≥1.10 atm. Initially there was a vacuum in one vessel while the other contained ideal gas at a temperature t₁ = 27 °C and pressure p₁ = 1.00 atm. Then both vessels were heated to a temperature t₂ =107 °C. Up to what value will the pressure in the first vessel (which had vacuum initially) increase ?

Answer 1

Let m be the mass of gas enclosed.

Then,  p₁v = v₁RT₁

When heated some gas, passes into the evacuated vessel till pressure difference becomes  Δp. Let p'₁ and p'₂ be the pressure on the two sides of the valve. Then p'₁v = v'₁RT₂ and  p'₂v = v'₂RT₂ = (v₁-v'₁)RT₂