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If `sin^4x/2+cos^4x/3=1/5`then
A. `tan^2x=2/3`
B. `sin^8x/8+cos^8x/27=1/125`
C. `tan^2x=1/3`
D. `sin^8/8+cos^8x/27=2/125`

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Correct Answer - A::B
`sin^4x/2+cos^4x/3=1/5`
`3sin^4x+2(1-sin^2x)^2=6/5`
`rArr 25sin^4x-20 sin^2 x+4=0`
`rArr sin^2x=2/5`
`:. cos^2x=3/5`
`:. tan^2x=2/3`
`and sin^8x/8+cos^8x/27=1/125`

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