Correct Answer - D
`(d)` Given equations are
`x^(2)-px+20=0`
`x^(2)-20x+p=0`
If `p=20` both the quadratic equations are identical hence `x=10+4sqrt(5)` or `x=10-4sqrt(5)`
If `p ne 20`, then subtracting equations, we get
`(20-p)x+(20-p)=0`
`implies x=-1`
Hence there are `3` values f `x`