Question

As a result of the isobaric heating by ΔT = 72 K one mole of a certain ideal gas obtains an amount of heat Q = 1..60 kJ. Find the work performed by the gas, the increment of its internal energy, and the value of   γ  = Cp/Cv.

Answer 1

 Under isobaric proces A = pΔV = RΔT (as v = 1) = 0.6kJ

From the first law of thermodynamics 

ΔU = Q - A = Q-RΔT = 1kJ