In an excited state of hydrogen like atom an electron has total energy of `-3.4 eV`. If the kinetic energy of the electron is E and its de-Broglie wavelength is `lambda`, then
A. `E=6.8 eV ,lamda~6.6xx10^(-10) m`
B. `E=3.4 eV ,lamda~6.6xx10^(-10) m`
C. `E=3.4 eV ,lamda~6.6xx10^(-11) m`
D. `E=6.8 eV ,lamda~6.6xx10^(-11) m`