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in Chemistry by (24.7k points)
Given `E_(Cr^(3+)//Cr)^(@)=-0.72V`, and
`E_(Fe^(2+)//Fe)^(@)=-0.42V`
The potential for the cell.
`Cr|Cr^(3+)(0.1M)||Fe^(2+)( 0. 01M)Fe` is
A. 0.339V
B. `0.339V`
C. `-0.26V`
D. 0.26V

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