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Given :
`Hg_(2)^(2+) +2 e ^(-)rightarrow 2Hg`, `E^(@) = 0.789 V` and `Hg^(2+) + 2e^(-) rightarrow Hg`, `E^(@) = 0.854V`
Calculate the equilibrium consant for `Hg_(2)^(2+) rightarrow Hg + Hg^(2+)`.
A. `3.13 xx 10^(-3)`
B. `3.13 xx 10^(-4)`
C. `6.26 xx 10^(-3)`
D. `6.26 xx 10^(-4)`

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