We have taken a saturated solution of `AgBr,K_(sp)` of AgBr is `12xx10^(-14)`. If `10^(-7)` "mole" of `AgNO_(3)` are added to 1 litre of this solution then the conductivity of this solution in terms of `10^(-7) Sm^(-1)` units will be: [Given: `lambda_((Ag^(+)))^(@)=4xx10^(-3)Sm^(2)"mol"^(-1),lambda_((Br^(-)))^(@)=6xx10^(-3) S m^(2) "mol"^(-1),lambda_((NO_(3)^(-)))^(@)=5xx10^(-3)Sm^(2) "mol"^(-1)`]
A. 39
B. 55
C. 15
D. 41
