Copper reduced `NO_(3)^(-)` into NO and `NO_(2)` depending upon cone. Of `HNO_(3)` in solution. Assuming `[Cu^(2+)]=0.1M` and `P

Copper reduced `NO_(3)^(-)` into NO and `NO_(2)` depending upon cone. Of `HNO_(3)` in solution. Assuming `[Cu^(2+)]=0.1M` and `P_(NO)=P_(NO_(2)=10^(-3)` atm and using given data answer the following question:
`E_(Cu^(2+)|Cu)^(@)=+0.34` volt
`E_(NO_(3)^(-)|NO)^(@)=+0.96` volt
`E_(NO_(#)^(-)|NO_(3))^(@)=+0.79` volt
at 298K `(RT)/(F)(2.303)=0.06` volt
At what `HNO_(3)` concentration thermodynamic tendency for reduction of `NO_(3)^(-)` into NO and `NO_(3)` by copper is same?
A. `10^(1//23)M`
B. `10^(0.56)M`
C. `10^(0.625)M`
D. `10^(0.12)M`

Copper reduced `NO_(3)^(-)` into NO and `NO_(2)` depending upon cone. Of `HNO_(3)` in solution. Assuming `[Cu^(2+)]=0.1M` and `P_(NO)=P_(NO_(2)=10^(-3

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