`H_(2)O_(2)` can be produced by the ammonium hydrogen sulphate. Reactions occuring in electrolytic cell,
`NH_(4)HSO_(4)rarrNH_(4)^(-)+2e^(-)` (Anode)
`2SO_(4)^(2-)rarrS_(2)O_(8)^(2-)+2e^(-)`
`2H^(+)+2e^(-)rarrH_(2)` (Cathode)
Hydrolysis of ammonium persulphate:
`(NH_(4))_(2)S_(2)O_(8)+2H_(2)Orarr2NH_(4)HSO_(4)+H_(2)O_(2)` Assume 100% yield of hydrolysis reaction.
How many "mole"s of electrons are to be passed in order to produce enough `H_(2)O_(2)` which when reacted with excess of KI then liberated iodine required 100 mL of centimolar hypo solution.
A. `10^(-1)`
B. `10^(-2)`
C. `10^(-3)`
D. `5xx10^(-4)`
