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in Physics by (25.2k points)
The de - Broglie wavelength `lambda` associated with an electron having kinetic energy `E` is given by the expression
A. `lamda = (h)/(mE)`
B. `lamda =(sqrt(2mE))/(h)`
C. `lamda=(h)/(2mE)`
D. `lamda =(h)/(sqrt(2mE))`

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