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`pH` of `0.01 M HS^(-)` will be:

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`pH` of `0.01 M HS^(-)` will be:
A. `pH=7+(pK_a)/2+(log C)/2`
B. `pH=7-(pK_a)/2+(log C)/2`
C. `pH=7+(pK_1+pK_2)/2`
D. `pH=7+((pK_a+pK_b)/2)`
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Correct Answer - a
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