Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Physics by (25.2k points)
In the figure a hemispherical bowl of bowl of radius R is shown Electric field of intensity E is present perpendicular to the circular cross section of the hemisohere.
image
A. The magnitude of electric flux through the hemispherical surface in sittation I will be `EpiR^(2)`
B. The magniude of electric flux through the hemisoherical surface in surface II will be `2EpiR^(2)`
C. the magnitude of electric flux thorugh the hemisperical surface in situation II will be `(EpiR^(2))/2`
D. the magnitude of electric flux through the hermispherical surface in situation II will be zero.

Please log in or register to answer this question.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...