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in Physics by (25.0k points)
When a metalic surface is illuminated with light of wavelength `lambda,` the stopping potential is V. the same surface is illuminated by light of wavelength `2lambda` the stopping potential is `(V)/(3)` The thershold waelength for the surface is
A. `(4lambda)/(3)`
B. `4lambda`
C. `6lambda`
D. `(8lambda)/(3)`

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