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+1 vote
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in Physics by (25.2k points)
The distance between the plates of a charged plate capacitor disconnected from the batteryis 5cm and the intensity of the field in it is `E=300V//cm`. An uncharged metal bar `1cm` thick is introduced into the capacitor parallel to its planes. The potential difference between the plates now is :
A. `1500V`
B. `1200V`
C. `900V`
D. Zero

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