Question

A network of resistors is connected to a battery of negligible internal resistance, as shown in figure. Calculate the equivalent resistance between the point A and D, and the value of the current `I_(3)`.

Answer 1

Correct Answer - `1.25Omega,0.5A`

Answer 2

Let's first find the current in the circuit. 

I=2A ....given

I₁₌​​​I₂=I/2=1A

I3=I4=I1/2=0.5A

Finding net resistance between point AD 

In AB and BC the currents are :

I1 flows from AB and I1-I3 flows from BC have different values so hence they are connected in parallel...

2*2/2+2=1Ω

Now ,

BC and CD have same values of current so we can take it as Series resistance.

1+2=3Ω

Now we consider CD and BD  Their currents are same so they are in series 

3+2=5

Νοω ιη ΒD   and  AD values of current are different so hence they are in parallel combination.

5×2/5+2=10/7=1.428~1.43 

Hence I3=0.5 and Req is nearer to 1.25 Value..hope this helps ..

Regards,,,

An aspirant who is learning through lots of mistakes ...

But it's okay to not be okay ...,!