`(IE)_(1)` and `(IE)_(2)` of `Mg_((g))` are `740, 1540 kJ mol^(-1)`. Calculate percentage of `Mg_((g))^(+)` and `Mg_((g))^(2+)` if 1g of `Mg_((g))` absorbs `50.0kJ` of energy.
A. `% Mg^(+) = 50` and `% Mg^(+2) = 50`
B. `% Mg^(+) = 70.13` and `%Mg^(+2) = 29.87`
C. `%Mg^(+) = 75` and `%Mg^(+2) = 25`
D. `%Mg^(+) = 60` and `%Mg^(+2) = 40`
