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The ionisation potential of `X_((g))^(-)` is numerically equal to

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in Chemistry by (24.0k points)
The ionisation potential of `X_((g))^(-)` is numerically equal to
A. E.A. of `X_((g))`
B. EA of `X_((g))^(+)`
C. E.A. of `X_((g))^(2-)`
D. E.A of `X_((g))^(2+)`
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1 Answer

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Correct Answer - A
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`X_((g))+e rarr X_((g))^(-) +E`, Here 'E' is
asked Sep 24, 2019 in Chemistry by AmritKaushik (24.0k points)

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