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An element "X" has `IP=1681` kJ/mole and `EA=-333` kJ/mole then its electronegativity is

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An element "X" has `IP=1681` kJ/mole and `EA=-333` kJ/mole then its electronegativity is
A. `1681+333//544`
B. `1681-333//544`
C. `1681+333//2`
D. `(0.208sqrt(1681+333))/(544)`
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Correct Answer - A
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