Statement-1: The reduction of a metal oxide is easier if the metal formed is in liquid state at the temperature of reduction.
Statement-2: The value of entropy changes `DeltaS` of the reduction process is more on + ve side when the metal formed is in liquid state and the metal oxide being reduced is in solid state. Thus the value of `DeltaG^(0)` becomes more on negative side.
A. Statement -1 is true, Statement-2 are true and Statement-2 is the correct explanation of Statement -1
B. Statement -1 is true, Statement-2 are true and Statement-2 is not a correct explanation of Statement -1
C. Statement-1 is true but Statement -2 is false
D. Statement-1 is false but Statement -2 is true