Question

Show that vectors a = 2i + 3j + 6k, b = 3i - 6j + 2k and c = 6i + 2j - 3k are mutually perpendicular.

Answer 1

As dot product of two perpendicular vectors is zero. Taking dot product of \(\vec{a}\) and \(\vec{b}\)

Combining two results, we can say that given three vectors \(\vec{a},\,\vec{b},\) and \(\vec{c}\) are mutually perpendicular to each other.