`XeO_(3)` forms xenate ion in alkaline medium. `XeO_(3) +NaOH rarr Na[HXeO_(4)]`
But the xenate ions slowly disproportionate in alkaline solution as
`Na[HXeO_(4)]+ NaOH rarr Z +Xe +O_(2) +H_(2)O` The compound Z is expected to be:
A. `Na_(2)XeO_(3)`
B. `Na_(2)XeO_(4)`
C. `Na_(4)XeO_(6)`
D. `Na_(4)XeO_(4)`
