Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
9.8k views
in Physics by (75.3k points)

When an uncharged conducting ball of radius R is placed in an external uniform electric field, a surface charge density σ = σ0 cos θ is induced on the ball's surface (here σ0 is a constant, θ is a polar angle). Find the magnitude of the resultant electric force acting on an induced charge of the same sign.

1 Answer

+1 vote
by (69.1k points)
selected by
 
Best answer

We know that the force acting on the area element dS of a conductor is,

It follows from symmetry considerations that the resultant force vector F directed along the z-axis, and hence it can be represented as the sum (integral) of the projection of elementary forces (1) onto the z-axis :

For simplicity let us consider an element area

Integrating this expression over the half sphere (i.e. with respect to cosθ between 1 and 0), we obtain

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...