Question

A projectile is thrown at an angle of 30° to the horizontal. What should be the range of initial velocity (u) so that its range will be between 40m and 50 m? Assume g = 10 m s^-2.

Answer 1

Given: 40 ≤ R ≤ 50, θ = 300, g = 10 m/s² 

To find: Range of initial velocity (u)

Formula: R = \(\frac{u^2\,sin(2θ)}{g}\)

Calculation: From formula, 

The range of initial velocity,

The range of initial velocity should be between 21.49 m/s ≤ u ≤ 24.03 m/s.