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The end product of `4n` series is a)`._(82)Pb^(208)` b)`._(82)Pb^(207)` c)`._(82)Pb^(209)` d)`._(82)Pb^(204)`

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The end product of `4n` series is a)`._(82)Pb^(208)` b)`._(82)Pb^(207)` c)`._(82)Pb^(209)` d)`._(82)Pb^(204)`
A. `._(82)^(208)Pb`
B. `._(82)^(207)Pb`
C. `._(82)^(209)Pb`
D. `._(83)^(210)Bi`
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Correct Answer - a
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