Question

A body is thrown with a velocity of 49 m/s at an angle of 30° with the horizontal. 

Find

(i) the maximum height attained by it

(ii) the time of flight and

(iii) the horizontal range.

Answer 1

Given: u = 49 m/s. θ = 30°

To find:

(i) The maximum height attained (H)

(ii) The time of flight (T)

(iii) The horizontal range (R)

Calculation: From formula (i),

(i) The maximum height attained by the body is 30.625 m

(ii) The time of flight of the body is 5 s.

(iii) The horizontal range of the body is 212.2 m.