The graph between two temperature scales `A` and `B` is shown in Fig. Between upper fixed point and lower fixed point there are `150` equal divisions on scales `A` and `100` on scale `B`. The relation between the temperature in two scales is given by_
A. `(t_(A)-180)/(100)=(t_(B))/(150)`
B. `(t_(A)-30)/(150)=(t_(B))/(100)`
C. `(t_(A)-180)/(150)=(t_(A))/(100)`
D. `(t_(B)-40)/(100)=(t_(A))/(180)`