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If `(cos theta)/(a)=(sintheta)/(b), then (a)/(sec 2 theta)+(b)/(cosec 2 theta)` is equal to

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If `(cos theta)/(a)=(sintheta)/(b), then (a)/(sec 2 theta)+(b)/(cosec 2 theta)` is equal to
A. a
B. b
C. `a/b`
D. `a+b`
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Correct Answer - A
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