1. If the object is on the surface of Earth, r = R
U1 = \(-\frac{GMm}{R}\)
If the object is lifted to height h above the surface of Earth, the potential energy becomes -GMm 12 ~~ R+h
U2 = \(-\frac{GMm}{R+h}\)
2. Increase in the potential energy is given by
3. If g is acceleration due to gravity on the surface of Earth. GM = gR2
∴ ∆U = mgh \((\frac{R}{R+h})\) … (1)
4. Equation (1) gives the work to be done to raise an object of mass rn to a height h, above the surface of the Earth.
5. If h << R, we can use R + h ≈ R.
∴ ∆U = mgh
Thus, mgh is increase in the gravitational potential energy of the Earth – mass system if an object of mass m is lifted to a height h, provided h << R.