Question

Find out one dinegative anion and one unipositive cation which are isoelectronic with Ne atom. Write their electronic configuration using orbital notations and orbital diagram method.

Answer 1

Atomic number (Z) of Ne is 10. 

Therefore,

Ne and its isoelectronic species contain 10 electrons each. 

The dinegative anionic species,isoelectronic with Ne is obtained by adding two electrons to the atom with Z = 8. This is O^2- ion.

The unipositive cationic species, isoelectronic with Ne is obtained by removing one electron from an atom with Z = 11. It is Na⁺ ion. 

These species and their electronic configurations are shown below :

	Number of electrons	Orbital notation	Orbital diagram
Ne	10	1s22s22p6
O + 2e- → O2-	8+2 = 10
Na+ e- → Na+	11-1 = 10