Triple point of water is, T = 273.16 K
Since the absolute scales measure the triple point as 200 A and 350 B.
∴ 200A = 350B = 273.16 K
∴ 1A = \(\frac{273.16}{200}\)K and 1B = \(\frac{273.16}{350}\)K
If TA and TB are the temperatures on the two scales, then
\(\frac{273.16}{200}\)TA = \(\frac{273.16}{350}\)TB
∴ TA = \(\frac{200}{350}\) TB = \(\frac{4}{7}\)TB
\(\frac{T_A}{T_B}=\frac{4}{7}\)
The relation between TA and TB is TA : TB = 4 : 7