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A particle of unit mass undergoes one dimensional motion such that its velocity varies according to v(x) = β x-2n, where B and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by

(a) -2β2x-2n+1

(b) -2nβ2e-4n+1

(c) -2nβ2x-2n-1

(d) -2nβ2x-4n-1

1 Answer

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Best answer

Correct option (d) -2nβ2x-4n-1

Explanation:

According to question, velocity of unit mass varies as

v(x) = β x-2n   ...(i)

dv/dx = -2nβ2x-2n-1

Acceleration of the particle is given by

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