Question

A negligibly small current is passed through a wire of length 15 m and uniform cross-section 6 × 10^-7 m², and its resistance is measured to be 5 Ω. What is the resistivity of the material at the temperature of the experiment?

Answer 1

Given: l = 15 m, A = 6.0 × 10^-7 m², R = 5 Ω

To find: Resistivity (ρ)

Formula: ρ = \(\frac{RA}{l}\)

Calculation: From formula,

ρ = \(\frac{5\times6\times10^{-7}}{15}\)

∴ ρ = 2 × 10^-7 Ω m