Question

62. The van der Waal and covalent radii or fluorine atom respectively from the following figure are a) \( 219 pm , 72 pm \) b) \( 75 pm , 72 pm \) c) \( 147 pm , 72 pm \). d) \( 147 pm , 144 pm \)

Answer 1

Vander waals radius - is equal to one Half the distance between two unbonded atoms.

Vander waals radius = \(\frac{X}{2}\)

⇒ \(\frac{294\,pm}{2}\) = 147 pm

Covalent radii -

One-half the distance between the Nuclei of two covalenty bonded atoms of the same element in a molecule.

∴ Covalent radii = \(\frac{Y}{2}\)

⇒ \(\frac{144\,pm}{2}\) = 72 pm

Hence,

Vander waals radius of f₂ molecule will be 147 pm and covalent radii of f₂ will be 72 pm.

Option (C) is correct.