In the first case image us five tunes magnified. Hence, |v| = 5|u|, In the second case image and object are of equal size. Hence, |v| = |u|. From the two figures,
![](https://www.sarthaks.com/?qa=blob&qa_blobid=10718368613821048098)
Using the lens formula for both the cases,
![](https://www.sarthaks.com/?qa=blob&qa_blobid=13076330479772853216)
Solving these three equations, we get
x = 0.1875 m and f = 0.15625 m
Therefore, initial distance between the object and the screen = 6x = 1.125 m
Power of the lens,
![](https://www.sarthaks.com/?qa=blob&qa_blobid=3270717751018889693)
![](https://www.sarthaks.com/?qa=blob&qa_blobid=15736900876740593309)