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in Physics by (45.3k points)

A converging lens forms a five fold magnified image of an object. The screen is moved towards the object by a distance d = 0.5 m, and the lens is shifted so that the image has the same size as the object. Find the lens power and the initial distance between the object and the screen.

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In the first case image us five tunes magnified. Hence, |v| = 5|u|, In the second case image and object are of equal size. Hence, |v| = |u|. From the two figures,

Using the lens formula for both the cases,

Solving these three equations, we get

x = 0.1875 m and f = 0.15625 m

Therefore, initial distance between the object and the screen = 6x = 1.125 m

Power of the lens,

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